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प्रश्न
How is the fringe width of an interference pattern in Young's double-slit experiment affected if the two slits are brought closer to each other?
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उत्तर
Fringe width, β = `(lambda D)/d`
∴ If d (= separation of slit ) decreases, β will increase.
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संबंधित प्रश्न
In Young' s experiment the ratio of intensity at the maxima and minima . in the interference pattern is 36 : 16. What is the ratio of the widths of the two slits?
In a double-slit experiment using the light of wavelength 600 nm, the angular width of the fringe formed on a distant screen is 0.1°. Find the spacing between the two slits.
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(A) equal width with same intensity
(B) unequal width with varying intensity
(C) equal intensity\
(D) equal width with varying intensity
In Young’s double slit experiment using monochromatic light of wavelength λ, the intensity of light at a point on the screen where path difference is λ, is K units. Find out the intensity of light at a point where path difference is λ/3.
In Young’s experiment interference bands were produced on a screen placed at 150 cm from two slits, 0.15 mm apart and illuminated by the light of wavelength 6500 Å. Calculate the fringe width.
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A thin transparent sheet is placed in front of a Young's double slit. The fringe-width will _____________ .
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- Assertion (A): In Young's double slit experiment all fringes are of equal width.
- Reason (R): The fringe width depends upon the wavelength of light (λ) used, the distance of the screen from the plane of slits (D) and slits separation (d).
What happens to fringe width when slit separation increases while wavelength and screen distance remain unchanged?
