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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Given A(4, –3), B(8, 5). Find the Coordinates of the Point that Divides Segment Ab in the Ratio 3 : 1.

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प्रश्न

Given A(4, –3), B(8, 5). Find the coordinates of the point that divides segment AB in the ratio 3 : 1.

बेरीज
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उत्तर

Let the coordinate of the point which divide the line AB in the ratio 3 : 1 be P(a, b)

\[a = \frac{3 \times 8 + 1 \times 4}{3 + 1} = \frac{24 + 4}{4} = 7\]

\[b = \frac{3 \times 5 + 1 \times \left( - 3 \right)}{3 + 1} = \frac{15 - 3}{4} = 3\]

P(a, b) = (7, 3)

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पाठ 5: Co-ordinate Geometry - Problem Set 5 [पृष्ठ १२३]

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बालभारती Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
पाठ 5 Co-ordinate Geometry
Problem Set 5 | Q 17 | पृष्ठ १२३

संबंधित प्रश्‍न

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Solution:

Point P divides segment AB in the ratio m : n.

A(8, 9) = (x1, y1), B(1, 2) = (x2, y2) and P(6, 7) = (x, y)

Using Section formula of internal division,

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∴ 7m – `square` = 9n – `square`

∴ `square` = 2n

∴ `m/n = square`


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