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प्रश्न
Give reason for the following:
When barium chloride is added to dilute sulphuric acid, a white precipitate is formed.
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उत्तर
When barium chloride is added to dilute sulphuric acid, a white precipitate of barium sulphate is
\[\ce{BaCl2 + H2SO4 -> BaSO4 v + 2HCl}\]
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संबंधित प्रश्न
State your observations when Concentrated Sulphuric acid is added to Sugar Crystals
Identify the acid in the following case:
The acid which produces sugar charcoal from sugar.
Give a chemical test to distinguish between dilute sulphuric acid and dilute hydrochloric acid.
Name the products formed when hot and concentrated sulphuric acid reacts with Carbon.
What do you observe when barium chloride solution is added to dilute sulphuric acid ?
A, B, C and D summarize the properties of sulphuric acid depending on whether it is dilute or concentrated. Choose the property (A, B, C or D), depending on which is relevant to each of the preparations (i) to (ii).
A. Dilute acid (typical acid properties)
B. Non-volatile acid
C. Oxidizing agent
D. Dehydrating agent
(i) Preparation of hydrogen chloride.
(ii) Preparation of ethane from ethanol
(iii) Preparation of copper sulphate from copper oxide.
Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation each to illustrate the properties of sulphuric acid mentioned above.
Write the balanced chemical equation for the following conversion:
Copper sulphate from copper and concentrated sulphuric acid.
Identify the gas evolved and give the chemical test in the following case:
Dilute hydrochloric acid reacts with sodium sulphite.
A, B and C are the chemical properties of sulphuric acid:
A. Oxidizing agent
B. Dehydrating agent
C. Non-volatile acid
Match the following equations 1 to 3 to the above chemical properties of sulphuric acid.
1. \[\ce{KNO3 + H2SO4 -> KHSO4 + HNO3}\]
2. \[\ce{C12H22O11 -> 12C + 11H2O}\]
3. \[\ce{S + 2H2SO4 -> 2H2O + 3SO2}\]
