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प्रश्न
Distinguish between the given pair of compounds using the test given within brackets:
Sodium nitrate and sodium sulphite (using dilute sulphuric acid).
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उत्तर
Sodium sulphite reacts with dilute H2SO4 to produce SO2 gas.
\[\ce{Na2SO3 + H2SO4 -> Na2SO4 + H2O + SO2 ^}\]
Sodium nitrate does not react with dilute H2SO4, so no gas is evolved.
\[\ce{NaNO3 + dil. H2SO4 -> No visible reaction}\]
संबंधित प्रश्न
State the conditions required for the given reaction to take place:
Any two conditions for the conversion of sulphur dioxide to sulphur trioxide
Why is H2SO4 is not used as a drying agent for H2S?
Name the following:
Products obtained by treating zinc with dilute sulphuric acid.
Name the following:
Products obtained by treating ferrous sulphide with dilute sulphuric acid.
Name the following:
The precipitate obtained by treating aqueous barium chloride with dilute sulphuric acid.
What would you observe in the following case?
Hot concentrated sulphuric acid is added to sodium chloride crystals.
Give reason for the following:
H2SO4 cannot be prepared by heating sodium sulphate with conc. HCl or HNO3
Write the equation for the laboratory preparation of the following salts, using sulphuric acid.
Iron (II) sulphate from iron.
Write the equation of the following reaction:
Sulphur is heated with concentrated sulphuric acid.
The salt is formed when concentrated sulphuric acid reacts with KNO3 above 200°C.
