Advertisements
Advertisements
प्रश्न
For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.

Advertisements
उत्तर
Using law of exponents,
am × an = (a)m + n ...[∵ a is non-zero integer]
Hook-up machine’s work = (0.5)2 × (0.5)3 = (0.5)5 ...[∵ am × an = am + n]
So, (×(0.5)5) machine can for the same work.
Diagram of single ×(0.5)5 machine.

APPEARS IN
संबंधित प्रश्न
The value of `(2/5)^-2` is ______.
(–9)3 ÷ (–9)8 is equal to ______.
55 × 5–5 = ______.
The value for (–7)6 ÷ 76 is ______.
`(2/3)^-2 xx (2/3)^-5 = (2/3)^10`
By what number should (–15)–1 be divided so that quotient may be equal to (–15)–1?
Find a single repeater machine that will do the same work as hook-up.

For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.

If possible, find a hook-up of prime base number machine that will do the same work as the given stretching machine. Do not use (× 1) machines.

Simplify:
`[(1/2)^2 - (1/4)^3]^-1 xx 2^-3`
