Advertisements
Advertisements
प्रश्न
For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.
Advertisements
उत्तर
Using law of exponents,
am × an = (a)m + n ...[∵ a is non-zero integer]
Hook-up machine can do the work = 122 × 123 = 125 ...[∵ am × an = (a)m + n]
So, (×125) machine can do the same work.
Diagram of ×125 single machine.
APPEARS IN
संबंधित प्रश्न
`(-5/7)^-5` is equal to ______.
`(1/10)^0` is equal to ______.
Which of the following is not the reciprocal of `(2/3)^4`?
By multiplying (10)5 by (10)–10 we get ______.
(–4)–4 × (4)–1 = (4)5
Simplify:
`(49 xx z^-3)/(7^-3 xx 10 xx z^-5) (z ≠ 0)`
By what number should (–15)–1 be divided so that quotient may be equal to (–15)–1?
For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.
The left column of the chart lists the lengths of input chains of gold. Repeater machines are listed across the top. The other entries are the outputs you get when you send the input chain from that row through the repeater machine from that column. Copy and complete the chart.
| Input Length | Repeater Machine | ||
| × 23 | |||
| 40 | 125 | ||
| 2 | |||
| 162 | |||
Find x.
5x + 5x – 1 = 750
