Advertisements
Advertisements
प्रश्न
Simplify:
`(1/5)^45 xx (1/5)^-60 - (1/5)^(+28) xx (1/5)^-43`
Advertisements
उत्तर
Given, `(1/5)^45 xx (1/5)^-60 - (1/5)^(+28) xx (1/5)^-43`
= `1/(5)^45 xx 1/(5)^-60 - 1/(5)^28 xx 1/(5)^-43` ...[∵ am × an = (a)m + n]
= `1/(5)^(45 - 60) - 1/(5)^(28 - 43)`
= `1/(5)^-15 - 1/(5)^-15` ...`[∵ a^-m = 1/a^m]`
= `(5)^15 - (5)^15`
= 0
APPEARS IN
संबंधित प्रश्न
If x be any non-zero integer and m, n be negative integers, then xm × xn is equal to ______.
55 × 5–5 = ______.
The expontential form for `(-2)^4 xx (5/2)^4` is 54.
Solve the following:
100–10
Simplify:
`(((-2)/3)^-2)^3 xx (1/3)^-4 xx 3^-1 xx 1/6`
In a repeater machine with 0 as an exponent, the base machine is applied 0 times. What do these machines do to a piece of chalk?

What happens when 1 cm worms are sent through these hook-ups?

Find a single repeater machine that will do the same work as hook-up.

Find a single repeater machine that will do the same work as hook-up.

Supply the missing information for diagram.

