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Fluorine reacts with ice and results in the change: HX2O(s)+FX2(g)⟶HF(g)+HOF(g) Justify that this reaction is a redox reaction. - Chemistry

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प्रश्न

Fluorine reacts with ice and results in the change: \[\ce{H2O(s) + F2(g) → HF(g) + HOF(g)}\]

Justify that this reaction is a redox reaction.

टीपा लिहा
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उत्तर

Let us write the oxidation number of each atom involved in the given reaction above its symbol as:
+1 -2         0              +1 -1        +1 -2 +1
\[\ce{H2O(s) + F2(g) → HF(g) + HOF(g)}\]

Here, we have observed that the oxidation number of F increases from 0 in F2 to +1 in HOF. Also, the oxidation number decreases from 0 in Fto –1 in HF. Thus, in the above reaction, F is both oxidized and reduced.
Hence, the given reaction is a redox reaction.

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Oxidation Number - Types of Redox Reactions
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