Advertisements
Advertisements
प्रश्न
Find the value of x, if sin 2x = 2 sin 45° cos 45°
Advertisements
उत्तर
sin 2x = 2 sin 45° cos 45°
sin 2x = `2(1/sqrt2)(1/sqrt2)`
sin 2x = 1 = sin 90°
2x = 90°
Hence, x = 45°
APPEARS IN
संबंधित प्रश्न
If `cosθ=1/sqrt(2)`, where θ is an acute angle, then find the value of sinθ.
if `tan theta = 12/5` find the value of `(1 + sin theta)/(1 -sin theta)`
if `cot theta = 1/sqrt3` find the value of `(1 - cos^2 theta)/(2 - sin^2 theta)`
Evaluate:
`cos70^circ/(sin20^circ) + cos59^circ/(sin31^circ) - 8 sin^2 30^circ`
Evaluate:
`(3sin72^@)/(cos18^@) - sec32^@/(cosec58^@)`
If 5 tan θ − 4 = 0, then the value of \[\frac{5 \sin \theta - 4 \cos \theta}{5 \sin \theta + 4 \cos \theta}\] is:
Find the sine ratio of θ in standard position whose terminal arm passes through (4,3)
A, B and C are interior angles of a triangle ABC. Show that
If ∠A = 90°, then find the value of tan`(("B+C")/2)`
If x tan 45° sin 30° = cos 30° tan 30°, then x is equal to ______.
If x tan 60° cos 60°= sin 60° cot 60°, then x = ______.
