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प्रश्न
Use tables to find the acute angle θ, if the value of tan θ is 0.7391
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उत्तर
From the tables, it is clear that tan 36° 24’ = 0.7373
tan θ − tan 36° 24’ = 0.7391 − 0.7373 = 0.0018
From the tables, diff of 4’ = 0.0018
Hence, θ = 36° 24’ + 4’ = 36° 28’
संबंधित प्रश्न
If `cosθ=1/sqrt(2)`, where θ is an acute angle, then find the value of sinθ.
Express each of the following in terms of trigonometric ratios of angles between 0º and 45º;
(i) cosec 69º + cot 69º
(ii) sin 81º + tan 81º
(iii) sin 72º + cot 72º
Express the trigonometric ratios sin A, sec A and tan A in terms of cot A.
Evaluate.
sin(90° - A) cosA + cos(90° - A) sinA
Evaluate:
cosec (65° + A) – sec (25° – A)
Prove that:
`(sinthetasin(90^circ - theta))/cot(90^circ - theta) = 1 - sin^2theta`
Evaluate: cos2 25° - sin2 65° - tan2 45°
Evaluate: `2(tan57°)/(cot33°) - (cot70°)/(tan20°) - sqrt(2) cos 45°`
Evaluate: `(cot^2 41°)/(tan^2 49°) - 2 (sin^2 75°)/(cos^2 15°)`
Choose the correct alternative:
If ∠A = 30°, then tan 2A = ?
