Advertisements
Advertisements
प्रश्न
Find the value of :
tan 225°
Advertisements
उत्तर
tan 225°= tan (180° + 45°)
= tan 45°
= 1
APPEARS IN
संबंधित प्रश्न
Find the value of:
sin 15°
Find the values of:
tan 105°
Find the value of :
sin (495°)
Find the value of :
cos 315°
Find the value of :
cos (600°)
Find the value of:
sec (–855°)
Find the value of :
cosec 780°
Find the value of :
cot (– 1110°)
Prove the following:
`(cos(pi + x) cos(-x))/(sin(pi - x)cos(pi/2 + x))` = cot2x
Prove the following:
cosθ + sin (270° + θ) − sin (270° − θ) + cos (180° + θ) = 0
Select the correct option from the given alternatives :
If sin θ = n sin (θ + 2α), then tan (θ + α) is equal to
Prove the following:
sin 20° sin 40° sin 80° = `sqrt(3)/8`
Prove the following:
cos 36° = `(sqrt(5) + 1)/4`
Prove the following:
sin 36° = `(sqrt(10 - 2sqrt(5)))/4`
Prove the following:
`tan pi/8 = sqrt(2) - 1`
Prove the following:
tan6° tan42° tan66° tan78° = 1
Prove the following:
sin47° + sin61° − sin11° − sin25° = cos7°
If a = sin 175°+ cos 175°, then ______.
If f(x) = `(2"x" + 3)/(3"x" - 2)`, `"x" ≠ 2/3`, then the function fof is ____________.
If θ = `(17π)/3` then, tan θ – cot θ = ______.
`(1 - 2[cos 60^circ - cos 80^circ])/(2 sin 10^circ)` = ______.
The value of `sin((25π)/3)` is ______.
The value of `2 cot^2(π/6) + 4 tan^2(π/6) - 3 "cosec"(π/6)` is ______.
The value of cos 480° sin 150° + sin 600° cos 390° is ______.
If cos θ = `- sqrt(3)/2` and sin α = `-3/5`, where θ does not and α lies in the third quadrant, then `(2 tan α + sqrt(3) tan θ)/(cot^2 θ + cos alpha)` is equal to ______.
In a ΔABC, if ∠A = `π/2`, then cos2 B + cos2 C is equal to ______.
The value of sin 930° is ______.
The value of cos(– 870°) is ______.
The value of sin 150° cos 120° + cos 330° sin 660° is ______.
The value of `2 sin^2 π/6 + "cosec"^2 (7π)/6 cos^2 π/3` is ______.
cos 1°. cos 2°. cos 3° ...... cos 179° = ______.
sin (270° – θ) sin (90° – θ) – cos ( 270° – θ) cos (90° + θ) is ______.
If x ≠ 0, then `(sin(pi + x)cos(pi/2 + x)tan((3pi)/2 - x)cot(2pi - x))/(sin(2pi - x)cos(2pi + x)cosec(-x)sin((3pi)/2 + x))` =
