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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Find the value of: sin 15° - Mathematics and Statistics

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प्रश्न

Find the value of:

sin 15°

बेरीज
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उत्तर

sin 15°

= sin (45° – 30°)

= sin 45° cos 30° – cos 45° sin 30°

= `(1/sqrt(2))(sqrt(3)/2) - (1/sqrt(2))(1/2)`

= `(sqrt(3) - 1)/(2sqrt(2)`

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Notes

Answer given in the textbook is `(sqrt(3) + 1)/(2sqrt(2)`. However, as per our calculation it is `(sqrt(3) - 1)/(2sqrt(2)`.

  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - 2 - Exercise 3.1 [पृष्ठ ३९]

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