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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Find the values of: cot 225° - Mathematics and Statistics

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प्रश्न

Find the values of:

cot 225°

बेरीज
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उत्तर

cot 225° = `1/tan225^circ`

= `1/(tan(180^circ + 45^circ)`

= `1/(((tan180^circ + tan45^circ)/(1 - tan180^circtan45^circ))`

= `1/(((0+1)/(1-0(1))))`

= `1/((1/1))`

= 1

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पाठ 3: Trigonometry - 2 - Exercise 3.1 [पृष्ठ ३९]

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