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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Find the value of: sec (–855°)

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प्रश्न

Find the value of:

sec (–855°) 

बेरीज
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उत्तर

We simplify the angle by adding or subtracting multiples of 360° until we get an angle between 0° and 360°.

−855 + 3 × 360 = −855 + 1080 = 225

sec (−855) = sec (225)

225 is in the third quadrant, where cosine is negative.

Reference angle: 225 − 180 = 45

cos ⁡(225) = −cos ⁡(45) = `-1/sqrt2`

sec (225) = `1/cos(225^\circ) = 1/(-1/sqrt2) = -sqrt2`

sec (−855) = `-sqrt2`

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पाठ 3: Trigonometry - 2 - Exercise 3.2 [पृष्ठ ४२]

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