Question

If x ≠ 0, then `(sin(pi + x)cos(pi/2 + x)tan((3pi)/2 - x)cot(2pi - x))/(sin(2pi - x)cos(2pi + x)cosec(-x)sin((3pi)/2 + x))` =

पर्याय

• 0

• −1

• 1

• 2

Answer 1

1

Explanation:

`(sin(pi + x)cos(pi/2 + x)tan((3pi)/2 - x)cot(2pi - x))/(sin(2pi - x)cos(2pi + x)cosec(-x)sin((3pi)/2 + x))`

where (x ≠ 0)

`((-sin x)(- sin x)(cot x)(- cot x))/((- sin x)(cos x)(-cosec x)(- cos x)) = 1`