मराठी

Find the value of: tan 15°

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प्रश्न

Find the value of: tan 15°

बेरीज
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उत्तर

tan 15° = tan (45° – 30°)

`(tan45° - tan30°)/(1+ tan45°tan30°)` (tan (A-B) = `(tanA-tanB)/(1+tan AtanB)`

`(1 - 1/sqrt(3))/(1 + 1 xx 1/sqrt(3))` .....`(tan pi = 1, tan 30 = 1/sqrt(3))`

= `((sqrt(3) - 1)/sqrt(3))/((sqrt(3) + 1)/sqrt(3))`

= `(sqrt(3) - 1)/(sqrt(3) + 1) xx (sqrt(3) - 1)/(sqrt(3) - 1)`

= `(sqrt(3) - 1)^2/(3 - 1)`

= `(3 + 1 - 2sqrt(3))/2`

= `(4 - 2sqrt(3))/2`

= `2 - sqrt(3)`.

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पाठ 3: Trigonometric Functions - EXERCISE 3.3 [पृष्ठ ६७]

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एनसीईआरटी Mathematics [English] Class 11
पाठ 3 Trigonometric Functions
EXERCISE 3.3 | Q 5. (ii) | पृष्ठ ६७

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