Advertisements
Advertisements
प्रश्न
Find the value of sin 0° + cos 0° + tan 0° + sec 0°.
पर्याय
2
1
3
0
Advertisements
उत्तर
2
Explanation:
sin 0° + cos 0° + tan 0° + sec 0° = 0 + 1 + 0 + 1 = 2
Thus, the value of sin 0° + cos 0° + tan 0° + sec 0° is 2.
APPEARS IN
संबंधित प्रश्न
Given sec θ = `13/12`, calculate all other trigonometric ratios.
If cot θ =` 7/8` evaluate `((1+sin θ )(1-sin θ))/((1+cos θ)(1-cos θ))`
In ΔABC, right angled at B. If tan A = `1/sqrt3` , find the value of
- sin A cos C + cos A sin C
- cos A cos C − sin A sin C
State whether the following are true or false. Justify your answer.
sec A = `12/5` for some value of angle A.
In the following, trigonometric ratios are given. Find the values of the other trigonometric ratios.
`cos A = 4/5`
if `sec A = 17/8` verify that `(3 - 4sin^2A)/(4 cos^2 A - 3) = (3 - tan^2 A)/(1 - 3 tan^2 A)`
If `sin theta = a/b` find sec θ + tan θ in terms of a and b.
Evaluate the following
`2 sin^2 30^2 - 3 cos^2 45^2 + tan^2 60^@`
Evaluate the Following
4(sin4 60° + cos4 30°) − 3(tan2 60° − tan2 45°) + 5 cos2 45°
Evaluate the Following
4(sin4 30° + cos2 60°) − 3(cos2 45° − sin2 90°) − sin2 60°
If cos (40° + A) = sin 30°, then value of A is ______.
5 tan² A – 5 sec² A + 1 is equal to ______.
Prove that: cot θ + tan θ = cosec θ·sec θ
Proof: L.H.S. = cot θ + tan θ
= `square/square + square/square` ......`[∵ cot θ = square/square, tan θ = square/square]`
= `(square + square)/(square xx square)` .....`[∵ square + square = 1]`
= `1/(square xx square)`
= `1/square xx 1/square`
= cosec θ·sec θ ......`[∵ "cosec" θ = 1/square, sec θ = 1/square]`
= R.H.S.
∴ L.H.S. = R.H.S.
∴ cot θ + tan θ = cosec·sec θ
Find will be the value of cos 90° + sin 90°.
Prove that `tan θ/(1 - cot θ) + cot θ/(1 - tanθ)` = 1 + sec θ cosec θ
The maximum value of the expression 5cosα + 12sinα – 8 is equal to ______.
If b = `(3 + cot π/8 + cot (11π)/24 - cot (5π)/24)`, then the value of `|bsqrt(2)|` is ______.
If cosec θ = `("p" + "q")/("p" - "q")` (p ≠ q ≠ 0), then `|cot(π/4 + θ/2)|` is equal to ______.
Evaluate 2 sec2 θ + 3 cosec2 θ – 2 sin θ cos θ if θ = 45°.
Evaluate: 5 cosec2 45° – 3 sin2 90° + 5 cos 0°.
