Advertisements
Advertisements
प्रश्न
Find the perimeter of a rectangle whose:
length = 8 m and breadth = 80 cm
Advertisements
उत्तर
length = 8 m and
breadth = 80 cm
Length = 8 m
Breadth = 80 cm
`=80/100 = 0.8 "m"`
∴ Perimeter = 2 (length + breadth)
= 2 (8 m + 0.8m)
= 2 x 8.8 m = 17.6 m
APPEARS IN
संबंधित प्रश्न
Each side of a rectangle is doubled. Find the ratio between :
(i) perimeters of the original rectangle and the resulting rectangle.
(ii) areas of the original rectangle and the resulting rectangle.
In each of the following cases, ABCD is a square and PQRS is a rectangle. Find, in each case, the area of the shaded portion.
(All measurements are in metre).
(i)
(ii)
The length and the breadth of a rectangular field are in the ratio 5: 4 and its area is 3380 m2. Find the cost of fencing it at the rate of ₹75 per m.
Find the perimeter of a rectangle whose:
length = 10 m and breadth = 8 m
Find the perimeter of an equilateral triangle of side 9.8 cm.
Each side of a square is 45 cm and a rectangle has length 50 cm. If the perimeters of both (square and rectangle) are same, find the breadth of the rectangle.
The perimeter of a rectangular field is 500 m and its length = 150 m. Find:
(i) its breadth,
(ii) its area.
(iii) cost of ploughing the field at the rate of ₹1.20 per square meter.
Length of a rectangle is three times its breadth. Perimeter of the rectangle is 40 cm. Find its length and width.
A large square is made by arranging a small square surrounded by four congruent rectangles as shown in the following figure. If the perimeter of each of the rectangle is 16 cm, find the area of the large square.
Why is the perimeter of a rectangle calculated as 2 × (length + breadth)?
