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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान इयत्ता ११

Find the derivatives of the following functions with respect to corresponding independent variables: y = sinx1+cosx

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प्रश्न

Find the derivatives of the following functions with respect to corresponding independent variables:

y = `sinx/(1 + cosx)`

बेरीज
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उत्तर

y = `sinx/(1 + cosx)`

= `u/v`  ....(say)

u = sin x  v = 1 + cos x

u’ = cos x v’ = – sin x

y = `u/v`

⇒ y' = `(vu"'" - uv"'")/v^2`

(i.e.,) `("d"y)/("d"x) = ((1 + cosx) cosx - sin(0 - sinx))/(1 + cosx)^2`

`("d"y)/("d"x) = (cosx + cos^2 x - sin^2x)/(1 + cosx)^2`

`("d"y)/("d"x) = (1 + cos x)/(1 + cosx)^2`

= `1/(1 + cosx)`

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Differentiation Rules
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.2 [पृष्ठ १६०]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.2 | Q 9 | पृष्ठ १६०

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