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Find the derivatives of the following functions with respect to corresponding independent variables: y = xsinx+cosx - Mathematics

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प्रश्न

Find the derivatives of the following functions with respect to corresponding independent variables:

y = `x/(sin x + cosx)`

बेरीज
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उत्तर

y = `x/(sin x + cosx)`

`("d"y)/("d"x) = ((sinx + cosx)(1) - x(cosx - sinx))/(sinx + cos x)^2`

`("d"y)/("d"x) = ((sinx + cosx)- x(cosx - sinx))/(sinx + cos x)^2`

`("d"y)/("d"x) = (sinx + cosx - xcosx + xsinx)/(sinx + cosx)^2`

`("d"y)/("d"x) = ((1 + x) sinx + (1 - x)cosx)/(sinx + cosx)^2`

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Differentiation Rules
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.2 [पृष्ठ १६०]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.2 | Q 10 | पृष्ठ १६०

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