Advertisements
Advertisements
प्रश्न
Find the derivatives of the following functions with respect to corresponding independent variables:
y = `(tanx - 1)/secx`
Advertisements
उत्तर
y = `(tanx - 1)/secx`
`("d"y)/("d"x) = (secx(sec^2x - 0) - (tan x - )secx tanx)/(sec x)^2`
`("d"y)/("d"x) = (secx[sec^2x - (tan x - 1) tanx])/(sec^2x)`
= `([sec^3x - tan^2xx + tanx])/secx`
= `((1 + tanx))/secx`
= `cos x (1 + sinx/cosx)`
`("d"y)/("d"x)` = cos x + sin x
APPEARS IN
संबंधित प्रश्न
Find the derivatives of the following functions with respect to corresponding independent variables:
f(x) = x sin x
Find the derivatives of the following functions with respect to corresponding independent variables:
y = cos x – 2 tan x
Find the derivatives of the following functions with respect to corresponding independent variables:
y = `sinx/x^2`
Find the derivatives of the following functions with respect to corresponding independent variables:
y = x sin x cos x
Find the derivatives of the following functions with respect to corresponding independent variables:
y = sin x0
Find the derivatives of the following functions with respect to corresponding independent variables:
Draw the function f'(x) if f(x) = 2x2 – 5x + 3
Differentiate the following:
F(x) = (x3 + 4x)7
Differentiate the following:
h(t) = `("t" - 1/"t")^(3/2)`
Differentiate the following:
y = e–mx
Differentiate the following:
y = sin2(cos kx)
Differentiate the following:
y = (1 + cos2)6
Differentiate the following:
y = `sqrt(x +sqrt(x)`
Differentiate the following:
y = `sin(tan(sqrt(sinx)))`
Find the derivatives of the following:
xy = yx
Find the derivatives of the following:
x = a (cos t + t sin t); y = a (sin t – t cos t)
Find the derivatives of the following:
Find the derivative of `sin^-1 ((2x)/(1 + x^2))` with respect to `tan^-1 x`
Find the derivatives of the following:
Find the derivative with `tan^-1 ((sinx)/(1 + cos x))` with respect to `tan^-1 ((cosx)/(1 + sinx))`
Choose the correct alternative:
If y = `1/4 u^4`, u = `2/3 x^3 + 5`, then `("d"y)/("d"x)` is
Choose the correct alternative:
If y = `1/("a" - z)`, then `("d"z)/("d"y)` is
