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Find the derivatives of the following: Find the derivative of sin-1(2x1+x2) with respect to tan-1x - Mathematics

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प्रश्न

Find the derivatives of the following:

Find the derivative of `sin^-1 ((2x)/(1 + x^2))` with respect to `tan^-1 x`

बेरीज
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उत्तर

Let u = `sin^-1 ((2x)/(1 + x^2))`

Put x = tan θ

u = `sin^-1 ((2tantheta)/(1 + tan^2theta))`

u = `sin^-1 (sin 2theta)`

u = 2θ

u = `2 tan^-1 (x)`

`("du")/("d"x) = 2/(1 + x^2)`     ...(1)

Let v = `tan^-1 x`

`("dv")/("d"x) = 2/(1 + x^2)`     ...(2)

From equations (1) and (2)

`(("du")/(dx))/(("dv")/(dx)) = (2/(1  +  x^2))/(1/(1  +  x^2))`

`("du")/("dv")` = 2

`("d"(sin^-1 ((2x)/(1  +  x^2))))/("d"(tan^-1 x))` = 2

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Differentiation Rules
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.4 [पृष्ठ १७६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.4 | Q 20 | पृष्ठ १७६

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