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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान इयत्ता ११

Differentiate the following:y = 1+x33

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प्रश्न

Differentiate the following:
y = `root(3)(1 + x^3)`

बेरीज
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उत्तर

y = `root(3)(1 + x^3)`

y = `(1 + x^3)^(1/3)`

[y = f(g(x)

`("d"y)/("d"x)` = f'(g(x)) . g'(x)]

`("d"y)/("d"x) = 1/3 (1 + x^3)^(1/3 - 1) xx "d"/("d"x) (1 + x^3)`

`("d"y)/("d"x) = 1/3 (1 + x^3)^(- 2/3) (0 + 3x^2)`

`("d"y)/("d"x) = 1/3 1/(1 + x^3)^(2/3) xx 3x^2`

`("d"y)/("d"x) = x^2/(1 + x^3)^(2/3)`

= `x^2 (1 + x^3)^(- 2/3)`

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Differentiation Rules
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.3 [पृष्ठ १६३]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.3 | Q 4 | पृष्ठ १६३

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