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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान इयत्ता ११

Differentiate the following: y = sin2xcosx

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प्रश्न

Differentiate the following:

y = `(sin^2x)/cos x`

बेरीज
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उत्तर

y = `(sin^2x)/cos x`

`("d"y)/("d"x) = (cosx(2sinx cos x) - sin^2x xx - sin x)/(cos x)^2`

`("d"y)/("d"x) = (2sinx cos^2x + sin^3x)/(cos^2x)`

= `sin x ((2 cos^2 x + sin^2 x))/(cos^2x)`

= `sin x((2cos2x)/(cos^2x) + (sin2x)/(cos2x))`

= sin x(2 + tan2x)

= sin x(1 + 1 + tan2x)

`("d"y)/("d"x)` = sin x(1 + sec2 x)

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Differentiation Rules
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.3 [पृष्ठ १६३]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.3 | Q 19 | पृष्ठ १६३

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