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Find the charge on each of the capacitors 0.20 ms after the switch S is closed in the figure.

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प्रश्न

Find the charge on each of the capacitors 0.20 ms after the switch S is closed in the figure.

संख्यात्मक
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उत्तर

The two 2.0 μF capacitors are in parallel, so Ceq = 2.0 + 2.0 = 4.0 μF.

With the 25 Ω series resistor and a 6.0 V battery:

τ = RC = (25) (4.0 × 10−6) = 1.0 × 10−4 s = 0.10 ms

At t = 0.20 ms = 2τ, the voltage across the capacitor bank is

VC​(t) = V(1 − e−t/τ) = 6.0 (1 − e−2) ≈ 6.0 (0.8647) ≈ 5.19 V.

Each parallel capacitor has this same voltage, so the charge on each:

Q = CV = (2.0μF) (5.19V) ≈ 1.04 × 10−5C = 10.4μC.

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पाठ 32: Electric Current in Conductors - Exercises [पृष्ठ २०३]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 32 Electric Current in Conductors
Exercises | Q 79 | पृष्ठ २०३

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