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प्रश्न
Find the area of the quadrilateral whose vertices are at (– 9, – 2), (– 8, – 4), (2, 2) and (1, – 3)
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उत्तर
Let the vertices A(– 9, – 2), B(– 8, – 4), C(2, 2) and D(1, – 3).
Plot the vertices in a graph.
Note: Consider the points in counter clockwise order
Area of the Quadrilateral = `1/2[(x_1y_2 + x_2y_3 + x_3y_4 + x_4y_1) - (x_2y_1 + x_3y_2 + x_4y_3 + x_1y_4)]`
Area of the Quadrilateral ABDC = `1/2[36 + 24 + 2 - 4 - (16 - 4 - 6 - 18)]`
= `1/2[58 - (- 12)] - 1/2 [58 + 12]`
= `1/2 xx 70`
= 35 sq. units
∴ The area of the quadrilateral is 35 sq. units.
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| Vertices | Area (sq.units) |
| (0, 0), (p, 8), (6, 2) | 20 |
