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प्रश्न
Find the 9th term of the series :
1, 4, 16, 64, ...............
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उत्तर
Given sequence: 1, 4, 16, 64, ...............
Now,
`4/1 = 4, 16/4 = 4, 64/16 = 4`
Since `4/1 = 16/4 = 64/16 = ...... = 4,` the given sequence is a G.P. with the first term, a = 1 and common ratio, r = 4.
Now, Tn = arn – 1
`\implies` T9 = 1 × 49 – 1
= 1 × 48
= 48
= 4 × 4 × 4 × 4 × 4 × 4 × 4 × 4
= 65536
संबंधित प्रश्न
Find, which of the following sequence from a G.P. :
9, 12, 16, 24, ................
Find the G.P. whose first term is 64 and next term is 32.
If the first and the third terms of a G.P. are 2 and 8 respectively, find its second term.
Find the seventh term from the end of the series :
`sqrt(2), 2, 2sqrt(2), ........., 32.`
If a, b and c are in G.P., prove that : log a, log b and log c are in A.P.
If a, b and c are in A.P, a, x, b are in G.P. whereas b, y and c are also in G.P.
Show that : x2, b2, y2 are in A.P.
Find the sum of G.P. :
`1 - 1/3 + 1/3^2 - 1/3^3 + .........` to n terms.
Q 3.1
The sum of three numbers in G.P. is `39/10` and their product is 1. Find the numbers.
Find the 5th term of the G.P. `5/2, 1, .........`
