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प्रश्न
Find the 9th term of the series :
1, 4, 16, 64, ...............
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उत्तर
Given sequence: 1, 4, 16, 64, ...............
Now,
`4/1 = 4, 16/4 = 4, 64/16 = 4`
Since `4/1 = 16/4 = 64/16 = ...... = 4,` the given sequence is a G.P. with the first term, a = 1 and common ratio, r = 4.
Now, Tn = arn – 1
`\implies` T9 = 1 × 49 – 1
= 1 × 48
= 48
= 4 × 4 × 4 × 4 × 4 × 4 × 4 × 4
= 65536
संबंधित प्रश्न
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Second term of a geometric progression is 6 and its fifth term is 9 times of its third term. Find the geometric progression. Consider that each term of the G.P. is positive.
Q 8
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Q 6
Find the sum of G.P. :
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Find the sum of G.P. :
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The first term of a G.P. is –3 and the square of the second term is equal to its 4th term. Find its 7th term.
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