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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Find Four Consecutive Terms in an A.P. Whose Sum is 12 and Sum of 3rd and 4th Term is 14. (Assume the Four Consecutive Terms in A.P. Are a – D, A, a + D, a +2d)

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प्रश्न

Find four consecutive terms in an A.P. whose sum is 12 and sum of 3rd and 4th term is 14.

(Assume the four consecutive terms in A.P. are a – d, a, a + d, a +2d) 

बेरीज
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उत्तर

Assume that the four consecutive terms in A.P. are a – d, a, a + d, a +2d . 

It is given that,
Sum of four consecutive terms = 12
Sum of 3rd and 4th term = 14

\[\left( a - d \right) + a + \left( a + d \right) + \left( a + 2d \right) = 12\]

\[ \Rightarrow 4a + 2d = 12\]

\[ \Rightarrow 2a + d = 6\]

\[ \Rightarrow 2a = 6 - d     . . . \left( 1 \right)\]

\[\left( a + d \right) + \left( a + 2d \right) = 14\]

\[ \Rightarrow 2a + 3d = 14\]

\[ \Rightarrow 6 - d + 3d = 14\]

\[ \Rightarrow 2d = 14 - 6\]

\[ \Rightarrow 2d = 8\]

\[ \Rightarrow d = 4 \left( \text { from} \left( 1 \right) \right)\]

\[ \Rightarrow 2a = 6 - d\]

\[ \Rightarrow 2a = 6 - 4\]

\[ \Rightarrow 2a = 2\]

\[ \Rightarrow a = 1\]

Hence, the terms are –3, 1, 5 and 9.

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पाठ 3: Arithmetic Progression - Practice Set 3.3 [पृष्ठ ७३]

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बालभारती Algebra Mathematics 1 [English] Standard 10 Maharashtra State Board
पाठ 3 Arithmetic Progression
Practice Set 3.3 | Q 8 | पृष्ठ ७३

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