मराठी

Show that a1, a2,..., an... form an AP where an is defined as below: an = 9 − 5n Also, find the sum of the first 15 terms.

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प्रश्न

Show that a1, a2,..., an... form an AP where an is defined as below:

an = 9 − 5n

Also, find the sum of the first 15 terms.

बेरीज
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उत्तर

an = 9 − 5n

a1 = 9 − 5 × 1

= 9 − 5

= 4

a2 = 9 − 5 × 2

= 9 − 10

= −1

a3 = 9 − 5 × 3

= 9 − 15

= −6

a4 = 9 − 5 × 4

= 9 − 20

= −11

It can be observed that

a2 − a1 = −1 − 4 = −5

a3 − a2 = −6 − (−1) = −5

a4 − a3 = −11 − (−6) = −5

i.e., ak + 1 − ak is same every time. Therefore, this is an A.P. with common difference as −5 and first term as 4.

`S_n = n/2 [2a + (n - 1)d]`

`S_15 = 15/2 [2(4) + (15 - 1) (-5)]`

= `15/2 [8 + 14(-5)]`

= `15/2 (8 - 70)`

= `15/2 (-62)`

= 15 × (-31)

= -465

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पाठ 5: Arithmetic Progressions - EXERCISE 5.3 [पृष्ठ ६९]

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एनसीईआरटी Mathematics [English] Class 10
पाठ 5 Arithmetic Progressions
EXERCISE 5.3 | Q 10. (ii) | पृष्ठ ६९

संबंधित प्रश्‍न

In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato and other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line.

A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run?

[Hint: to pick up the first potato and the second potato, the total distance (in metres) run by a competitor is 2 × 5 + 2 ×(5 + 3)]


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