Advertisements
Advertisements
प्रश्न
Write 5th term from the end of the A.P. 3, 5, 7, 9, ..., 201.
Advertisements
उत्तर
In the given problem, we need to find the 5th term from the end for the given A.P.
3, 5, 7, 9 …201
Here, to find the 5th term from the end let us first find the common difference of the A.P. So,
First term (a) = 3
Last term (an) = 201
Common difference (d) = 5 - 3 = 2
Now, as we know, the nth term from the end can be given by the formula,
an = l - (n-1) d
So, the 5th term from the end,
a5 = 201 - (5-1)2
= 201 - (4)2
= 201 - 8
= 193
Therefore, the 5th term from the end of the given A.P. is 193 .
APPEARS IN
संबंधित प्रश्न
Find the sum of all natural numbers between 250 and 1000 which are exactly divisible by 3
How many terms of the series 54, 51, 48, …. be taken so that their sum is 513 ? Explain the double answer
If the term of m terms of an A.P. is the same as the sum of its n terms, show that the sum of its (m + n) terms is zero
If the sum of first m terms of an A.P. is the same as the sum of its first n terms, show that the sum of its first (m + n) terms is zero
Find the sum of the following arithmetic progressions:
3, 9/2, 6, 15/2, ... to 25 terms
Which term of AP 72,68,64,60,… is 0?
If the sum of first m terms of an AP is ( 2m2 + 3m) then what is its second term?
How many terms of the AP 63, 60, 57, 54, ….. must be taken so that their sum is 693? Explain the double answer.
Find four consecutive terms in an A.P. whose sum is 12 and sum of 3rd and 4th term is 14.
(Assume the four consecutive terms in A.P. are a – d, a, a + d, a +2d)
If first term of an A.P. is a, second term is b and last term is c, then show that sum of all terms is \[\frac{\left( a + c \right) \left( b + c - 2a \right)}{2\left( b - a \right)}\].
If the sum of first p terms of an A.P. is equal to the sum of first q terms then show that the sum of its first (p + q) terms is zero. (p ≠ q)
The 9th term of an A.P. is equal to 6 times its second term. If its 5th term is 22, find the A.P.
Find the sum of n terms of the series \[\left( 4 - \frac{1}{n} \right) + \left( 4 - \frac{2}{n} \right) + \left( 4 - \frac{3}{n} \right) + . . . . . . . . . .\]
Sum of n terms of the series `sqrt2+sqrt8+sqrt18+sqrt32+....` is ______.
The term A.P is 8, 10, 12, 14,...., 126 . find A.P.
Q.13
Find the sum of all the 11 terms of an A.P. whose middle most term is 30.
Find the value of a25 – a15 for the AP: 6, 9, 12, 15, ………..
In an A.P., the sum of first n terms is `n/2 (3n + 5)`. Find the 25th term of the A.P.
The sum of A.P. 4, 7, 10, 13, ........ upto 20 terms is ______.
