मराठी

Find the Equation of the Circle Concentric with X2 + Y2 − 4x − 6y − 3 = 0 and Which Touches the Y-axis.

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प्रश्न

Find the equation of the circle concentric with x2 + y2 − 4x − 6y − 3 = 0 and which touches the y-axis.

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उत्तर

Since, the circles are concentric.

\[\Rightarrow\] Centre of required circle = Centre of x2 + y2 − 4x − 6y − 3 = 0
The centre of the required circle is (2, 3).
We know that if a circle with centre (h, k) touches the y-axis, then h is the radius of the circle.
Thus, the radius is 2.
∴ Equation of the circle: \[\left( x - 2 \right)^2 + \left( y - 3 \right)^2 = 2^2\]
\[\Rightarrow x^2 + y^2 - 4x - 6y + 9 = 0\]
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Advanced Concept of Circle - Standard Equation of a Circle
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पाठ 24: The circle - Exercise 24.2 [पृष्ठ ३२]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 24 The circle
Exercise 24.2 | Q 13 | पृष्ठ ३२

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