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Factorise : a - B - 4a2 + 4b2 - Mathematics

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प्रश्न

Factorise : a - b - 4a2 + 4b2

बेरीज
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उत्तर

a - b - 4a2 + 4b 
= ( a - b ) - 4( a2 - b2 )

= ( a - b ) - 4( a - b )( a + b )   [ ∵ a2 - b2 = ( a + b )( a - b )]

= ( a - b )[ 1 - 4( a + b )]

= ( a - b )[ 1 - 4a - 4b ]

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पाठ 5: Factorisation - Exercise 5 (E) [पृष्ठ ७६]

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सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 5 Factorisation
Exercise 5 (E) | Q 7 | पृष्ठ ७६

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