Advertisements
Advertisements
प्रश्न
factorise : 35a3b2c + 42ab2c2
Advertisements
उत्तर
35a3b2c + 42ab2c2 = 7ab2c (5a2 + 6c)
APPEARS IN
संबंधित प्रश्न
Find the common factors of the terms.
6 abc, 24ab2, 12a2b
Factorise the following expression:
7a2 + 14a
Factorise.
ax + bx − ay − by
Factorise.
15pq + 15 + 9q + 25p
Factorize the following:
2l2mn - 3lm2n + 4lmn2
Factories by taking out common factors :
ab(a2 + b2 - c2) - bc(c2 - a2 - b2) + ca(a2 + b2 - c2)
Factories by taking out common factors :
2x(a - b) + 3y(5a - 5b) + 4z(2b - 2a)
Factorise:
`x^2 + 1/(4x^2) + 1 - 7x - 7/(2x)`
Factorise: x4 + y4 - 3x2y2
Factorise : 3 - 5x + 5y - 12(x - y)2
Factorise : 9x 2 + 3x - 8y - 64y2
Factorise : 3x2 + 6x3
Factorise : 2b (2a + b) - 3c (2a + b)
Factorise : 4x(3x - 2y) - 2y(3x - 2y)
Factorise: 6xy(a2 + b2) + 8yz(a2 + b2) −10xz(a2 + b2)
factorise : 8(2a + 3b)3 - 12(2a + 3b)2
factorise : xy2 + (x - 1) y - 1
Factorise the following by taking out the common factors:
36(x + y)3 - 54(x + y)2
