Advertisements
Advertisements
प्रश्न
Find the common factors of the terms.
6 abc, 24ab2, 12a2b
बेरीज
Advertisements
उत्तर
The given terms are 6abc, 24ab2 and 12a2b
6abc = 2 × 3 × a × b × c
24ab2 = 2 × 2 × 2 × 3 × a × b × b
12a2b = 2 × 2 × 3 × a × a × b
The common factors are 2, 3, a, b.
And, 2 × 3 × a × b
= 6ab
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Find the common factors of the terms.
3x2y3, 10x3y2, 6x2y2z
Factorize the following:
2l2mn - 3lm2n + 4lmn2
Factorise : 2b (2a + b) - 3c (2a + b)
Factorise : 4x(3x - 2y) - 2y(3x - 2y)
Factorise : (a+ 2b) (3a + b) - (a+ b) (a+ 2b) +(a+ 2b)2
factorise : 8(2a + 3b)3 - 12(2a + 3b)2
Factorise xy2 - xz2, Hence, find the value of :
9 x 82 - 9 x 22
Factorise the following by taking out the common factors:
24m4n6 + 56m6n4 - 72m2n2
Factorise 12a2b+ 15ab2.
Factorise the following by taking out the common factor
9x5y3 + 6x3y2 – 18x2y
