Advertisements
Advertisements
प्रश्न
factorise: 8 + 6(a + b) - 5(a + b)2
बेरीज
Advertisements
उत्तर
8 + 6(a + b) - 5(a + b)2
Let a + b = x
(a + b)2 = x2
8 + 6 (a+b) - 5(a + b)2
= 8 + 6x - 5x2
= 8 + 10x - 4x - 5x2
= 2(4 + 5x) - x (4 + 5x)
= (4 + 5x)(2 - x)
= [4 + 5(a + b)] [2 - (a + b)]
(Substituting the value of x)
= [4 + 5a + 5b][2 - a - b]
shaalaa.com
Factorisation by Grouping
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method: 16 (a + b)2 - 4a - 4b
Factorise by the grouping method : a (a -4) - a + 4
Factorise : - x2y - x + 3xy + 3
Factorise : x2 - (b - 2)x - 2b
Factorise : a(b − c) − d(c − b)
factorise: x2 + 5xy + 4y2
factorise: 5 + 3a - 14a2
factorise: a2 - 23a + 42
Factorise the following by grouping the terms:
8(2a + b)2 - 8a -4b
Factorise the following by grouping the terms:
x2 - (p + q)x + pq
