Factorise: 2a2 + 7a + 6

factorise: 2a² + 7a + 6

बेरीज

2a² + 7a + 6

= 2a² + 4a + 3a + 6

= 2a(a + 2) + 3(a + 2)

= (a + 2)(2a + 3)

shaalaa.com

Factorisation by Grouping

या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

पाठ 13: Factorisation - Exercise 13 (D) [पृष्ठ १६१]

पाठ 13 Factorisation
Exercise 13 (D) | Q 10 | पृष्ठ १६१

Factorise by the grouping method : (2a-b)² -10a + 5b

Factorise using the grouping method :
m (x - 3y)² + n (3y - x) + 5x - 15y

Factorise : 3a²b - 12a² - 9b + 36

Factorise : ax + 2bx + 3cx - 3a - 6b - 9c

factorise: 15(5x - 4)² - 10(5x - 4)

factorise: 3a²x - bx + 3a² - b

Factorise the following by grouping the terms:
x(x - 4)- x + 4

Factorise the following by grouping the terms:
2m³ - 5n² - 5m²n + 2mn

Factorise the following by grouping the terms:
4abx² + 49aby² + 14xy(a² + b²)

Factorise the following by grouping the terms:
x² - (p + q)x + pq