Advertisements
Advertisements
प्रश्न
Factorise the following by grouping the terms:
4abx2 + 49aby2 + 14xy(a2 + b2)
बेरीज
Advertisements
उत्तर
4abx2 + 49aby2 + 14xy(a2 + b2)
= 4abx2 + 49aby2 + 14a2xy + 14b2xy
= (4abx2 + 14a2xy) + (14b2xy + 49aby2)
= 2ax(2bx + 7ay) + 7by(2bx + 7ay)
= (2bx + 7ay)(2ax + 7by).
shaalaa.com
Factorisation by Grouping
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method :
`a^2 + 1/a^2 - 2 - 3a + 3/a`
Factorise : ab2 - (a - c) b - c
Factorise : 2ab2c - 2a + 3b3c - 3b - 4b2c2 + 4c
factorise: a2 − 3a − 40
factorise: 2x2 + xy - 6y2
factorise: 8 + 6(a + b) - 5(a + b)2
factorise: (3x - 2y)2 - 5(3x - 2y) - 24
Factorise the following by grouping the terms:
9 + 3xy + x2y + 3x
Factorise the following by grouping the terms:
8x3 - 24x2y + 54xy2 -162y3
Factorise the following by grouping the terms:
`(1)/(25x^2) + 16x^2 + (8)/(5) - 12x - (3)/(5x)`
