Advertisements
Advertisements
प्रश्न
Explain why is \[\ce{O = C =O}\] nonpolar while \[\ce{R - O - R}\] is polar.
Advertisements
उत्तर
\[\ce{O = C =O}\] molecule is linear so that the polarities of two C – O bonds get cancelled and the molecule is linear.
Ethers have structures similar to water and have angular or bent structure. Therefore, the polarity of two R – O groups does not get cancelled and these have net dipole moment. Thus, \[\ce{R - O - R}\] is polar.
APPEARS IN
संबंधित प्रश्न
Write the structure of the product of the following reaction:
\[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CHO ->[NaBH4]}\\
|\phantom{....}\\
\ce{CH3}\\
\end{array}\]
Write the structure of the compound whose IUPAC name is as follows:
2-Methylbutan-2-ol
Write the structure of the compound whose IUPAC name is as follows:
1-Phenylpropan-2-ol
Write the structure of the compound whose IUPAC name is as follows:
3,5-Dimethylhexane-1, 3, 5-triol
Write the structure of the compound whose IUPAC name is as follows:
2,3-Diethylphenol
Write the structure of the compound whose IUPAC name is as follows:
1-Ethoxypropane
Write the structure of the compound whose IUPAC name is as follows:
2-Ethoxy-3-methylpentane
Write the structure of the compound whose IUPAC name is as follows:
Cyclohexylmethanol
Write the structure of the compound whose IUPAC name is as follows:
Cyclopent-3-en-1-ol
\[\ce{CH3-O-CH(CH3)2 + HI ->}\] Products is/are:
What is the structure and IUPAC name of glycerol?
Glycerol is used
Diethyl ether finds are in medicine as
Wine (alcoholic beverages) contains
\[\begin{array}{cc}\phantom{......}\ce{OH}\\
\phantom{....}|\\\ce{CH3CH2 - C - CH3}\\
\phantom{....}|\\\phantom{.....}\ce{Ph}\end{array}\] cannot be prepared by ______.
Write the structure of the compound whose IUPAC name is as follows:
4-Chloro-3-ethylbutan-1-ol
Give IUPAC name of the compound given below.
\[\begin{array}{cc}
\phantom{.}\ce{CH3 - CH - CH2-CH2-CH-CH3}\\
\phantom{.}|\phantom{............................}|\\
\phantom{....}\ce{Cl}\phantom{.........................}\ce{OH}\\
\end{array}\]
