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प्रश्न
Explain the following reaction with the balanced equation.
Zinc carbonate is heated strongly in limited supply of air
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उत्तर
Zinc carbonate is heated strongly in a limited supply of air to convert it to zinc oxide. This process is called calcination.
\[\ce{\underset{\text{Zinc carbonate}}{ZnCO_{3(s)}} ->[Heat] \underset{\text{Zinc oxide}}{ZnO_{(s)}} + \underset{\text{Carbon dioxide}}{CO_2↑}}\]
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संबंधित प्रश्न
M is a metal above hydrogen in the activity series and its oxide has the formula M2O. This oxide when dissolved in water forms the corresponding hydroxide which is a good conductor of electricity. In the above context, answer the following:
1) What kind of combination exists between M and O?
2)How many electrons are there in the outermost shell of M?
3) Name the group to which M belongs.
4) State the reaction taking place at the cathode.
5) Name the product at the anode.
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Name the following :
The Process of heating an ore to a high temperature in the presence of air.
Name the process used for the enrichment of sulphide ore.
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Reason (R): Roasting converts sulphide ores directly into metals.
