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प्रश्न
Explain giving reasons:
Transition metals and many of their compounds show paramagnetic behaviour.
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उत्तर
Paramagnetism in substances arises from the presence of unpaired electrons. Diamagnetic substances are those in which all the electrons are paired. Transition metal ions exhibit both diamagnetism and paramagnetism, i.e., two opposite effects, so the calculated magnetic moment is considered their resultant. Except for d0 (Sc3+, Ti4+) or d10 (Cu+, Zn2+) configurations, all simple ions of transition metals have unpaired electrons in their (n – 1)d subshells; hence, they are mostly paramagnetic. The magnetic moment of such an unpaired electron is related to spin angular momentum and orbital angular momentum. In compounds of metals of the first transition series, the contribution of orbital angular momentum is effectively quenched; hence, it is of no significance.
Therefore, the magnetic moment for them is determined on the basis of the number of unpaired electrons present in it, and it is calculated by the following ‘spin only’ formula.
μ = `sqrt (n(n + 2))`
Here, n is the number of unpaired electrons, and II is the magnetic moment, whose unit is the Bohr magneton (BM). Hence, the magnetic moment of an unpaired electron is 1.73 BM.
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संबंधित प्रश्न
Write down the electronic configuration of Cr3+.
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Which among the following elements does not belong to the first transition series?
Electronic configuration of Cu3+ is ____________.
Electronic configuration of manganese (Z = 25) is ______
Explain the observation, at the end of each period, there is a slight increase in the atomic radius of d-block elements.
Name the element of 3d series which exhibits the largest number of oxidation states. Give reason.
Define transition metals.
Match the properties with the elements of 3d series:
| (i) | lowest enthalpy of atomisation | (p) | Sc |
| (ii) | shows maximum number of oxidation states | (q) | Mn |
| (iii) | transition metal that does not form coloured compounds |
(r) | Zn |
| (s) | Ti |
Write down the electronic configuration of:
\[\ce{CO^2+}\]
