मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Explain formula mass with an example. - Chemistry

Advertisements
Advertisements

प्रश्न

Explain formula mass with an example.

टीपा लिहा
Advertisements

उत्तर

  1. The formula mass of a substance is the sum of atomic masses of the atoms present in the formula.
  2. In substances such as sodium chloride, positive (sodium), and negative (chloride) entities are arranged in a three-dimensional structure in a way that one sodium (Na+) ion is surrounded by six chlorides (Cl) ions, all at the same distance from it and vice versa. Thus, sodium chloride does not contain discrete molecules as the constituent units.
  3. Therefore, NaCl is just the formula that is used to represent sodium chloride though it is not a molecule.
  4. In such compounds, the formula (i.e., NaCl) is used to calculate the formula mass instead of molecular mass.
    e.g. Formula mass of sodium chloride = atomic mass of sodium + atomic mass of chlorine
    = 23.0 u + 35.5 u
    = 58.5 u
shaalaa.com
Atomic and Molecular Masses
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Some Basic Concepts of Chemistry - Exercises [पृष्ठ १२]

APPEARS IN

बालभारती Chemistry [English] Standard 11 Maharashtra State Board
पाठ 1 Some Basic Concepts of Chemistry
Exercises | Q 5. (D) | पृष्ठ १२

संबंधित प्रश्‍न

The number of molecules in 22.4 cm3 of nitrogen gas at STP is ______.


Which of the following has the largest number of atoms?


Calculate the molecular mass of the following in u.

CH3COOH


Calculate the molecular mass of the following in u.

C2H5OH


Solve problem:

The mass of an atom of hydrogen is 1.008 u. What is the mass of 18 atoms of hydrogen?


Solve problem:

Calculate the number of an atom of the following (Given: Atomic mass of I = 127 u).

254 u of iodine (I)


Solve problem:

Calculate the number of atoms of the following. (Average atomic mass : N = 14 u, S = 32 u)

0.4 mole of nitrogen


Solve problem:

Calculate the number of moles of magnesium oxide, MgO in

  1. 80 g, and
  2. 10 g of the compound.

(Average atomic masses of Mg = 24 and O = 16)


Solve problem:

Calculate the mass of sulfur dioxide produced by burning 16 g of sulfur in excess of oxygen in the contact process. (Average atomic mass : S = 32 u, O = 16 u)


Which one of the following represents 180 g of water?


Two 22.4 litre containers A and B contains 8 g of O2 and 8 g of SO2 respectively at 273 K and 1 atm pressure, then


What is the mass of precipitate formed when 50 ml of 8.5% solution of AgNO3 is mixed with 100 ml of 1.865% potassium chloride solution?


The reaction between aluminium and ferric oxide can generate temperatures up to 3273 K and is used in welding metals.
(Atomic mass of Al = 27 u Atomic mass of O = 16 u)
\[\ce{2Al + Fe2O3 -> Al2O3 + 2Fe}\]; If, in this process, 324 g of aluminium is allowed to react with 1.12 kg of ferric oxide.

  1. Calculate the mass of Al2O3 formed.
  2. How much of the excess reagent is left at the end of the reaction?

How many moles of ammonia are present in 5.6 cm3 of ammonia gas at STP?


What is the average mass of an element if it has two isotopes, one of mass 6.015 u with 8.24 % and other of mass 7.016 u with 91.26% respectively?


The unit of atomic mass, amu is replaced by u, here u stands for ______.


One amu is equal to ________.


Calculate mass of 3.01 × 1024 atoms of an element having atomic mass 21.13.


A 100 g of sample of haemoglobin on analysis was found to contain 0.34% Fe by mass. If each haemoglobin molecule has four Fe2+ ions, the molecular mass of haemoglobin is: (Fe = 56 amu)


It is found that in 11.2 L at 0°C and 1 atm, of any gaseous compound of 'X', there is never less than 15.5 gm of 'X'. It is also found that 11.2 L of vapours of 'X' at 0°C and 1 atm, weighs 62 gm. The atomicity of 'X' is ______.


Which symbol replaces the unit of atomic mass, amu?


0.05 F electricity is passed through CuSO4 solution. Calculate the mass of Cu produced at cathode? (molar  mass of Cu = 63.5 g mol-1)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×