Question

A uniform magnetic field of `0.20 xx 10^-3  "T"`  exists in the space. Find the change in the magnetic scalar potential as one moves through 50 cm along the field.

Answer 1

Given : 

Magnetic field in the space, B = `0.20 xx 10^-3  "T"`

Distance moved, `Δr = 50  "cm"`

We know , 

`B = -(dV)/(dl)`

⇒ `dV = ∫_(r_1)^(r^2) -  vec B.dl`

Since the magnetic field is uniform, it can come out of the integration sign.

⇒ `ΔV = - B.(Δr)`

here , `ΔV` is the change in the potential 

`therefore` Change in the potential = `-0.2 xx 10^-3 xx 0.5`

= `-0.1 xx 10^-3   "T-m"`

Here, the negative sign shows that the potential decreases.