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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान इयत्ता ११

Evaluate the following limits: limx→∞(x2-2x+1x2-4x+2)x

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प्रश्न

Evaluate the following limits:

`lim_(x -> oo) ((x^2 - 2x + 1)/(x^2 -4x + 2))^x`

बेरीज
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उत्तर

`lim_(x -> oo) ((x^2 - 2x + 1)/(x^2 -4x + 2))^x =  lim_(x -> oo) ((x^2 - 4x + 2 + 2x - 1)/(x^2 - 4x + 2))^x`

= `lim_(x -> oo) [(x^2 - 4x - 2)/(x^2 - 4x + 2) +(2x - 1)/(x^2 - 4x + 2)]^x`

= `lim_(x -> oo) [1 + (2x - 1)/(x^2 - 4x + 2)]^x`

= `lim_(x - oo) [1 + 1/((x^2 -4x + 2)/(2x - 1))]^(((x^2 - 4x + 2)/(2x - 1) xx ((2x - 1)x)/(x^2 - 4x + 2))`

= `lim_(x -> oo) [(1 + (2x - 1)/(x^2 - 4x + 2))^((x^2 - 4x + 2)/(2x - 1))]^(((2x - 1)x)/(x^2 - 4x + 2))`

`lim_(x -> oo) ((x^2 - 2x + 1)/(x^2 - 4x + 2))^x = [lim_(x -> oo) "e"]^((2x^2 - x)/(x^2 - 4x + 2))`

`lim_(x -> oo) (1 + 1/x)^x`  = e

= `"e"^(lim_(x ->oo)) ((2x^2 - x)/(x^2 - 4x + 2))`

= `"e"^(lim_(x -> oo) (x^2(2 -x/x^2))/(x^2(1 - (4x)/(x^2) + 2/x^2))`

= `"e"^(lim_(x ->oo) ((2 - 1/x)/(1 -4/x + 2/x^2))`

= `"e"^(((2 - 0)/(1 - 0 + 0))`

`lim_(x -> oo) ((x^2 - 2x + 1)/(x^2 -4x + 2))^x` = e2 

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पाठ 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [पृष्ठ ११८]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 24 | पृष्ठ ११८

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