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In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why? limx→1sinπx

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प्रश्न

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 1) sin pi x`

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उत्तर

`lim_(x -> 1) sin pi x`

From the graph x = 1, the curve y = f(x) intersects the line x = 1 at x – axis.

∴ y = f(1) = 0

Hence `lim_(x -> 1) sin pix` = 0

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Differential Calculus - Limits and Continuity - Exercise 9.1 [पृष्ठ ९७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 9 Differential Calculus - Limits and Continuity
Exercise 9.1 | Q 13 | पृष्ठ ९७

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