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Choose the correct alternative: limα-π4sinα-cosαα-π4 is

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प्रश्न

Choose the correct alternative:

`lim_(alpha - pi/4) (sin alpha - cos alpha)/(alpha - pi/4)` is

पर्याय

  • `sqrt(2)`

  • `1/sqrt(2)`

  • 1

  • 2

MCQ
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उत्तर

`sqrt(2)`

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Differential Calculus - Limits and Continuity - Exercise 9.6 [पृष्ठ १३०]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 9 Differential Calculus - Limits and Continuity
Exercise 9.6 | Q 15 | पृष्ठ १३०

संबंधित प्रश्‍न

Evaluate the following limit:

`lim_(z -> -5)[((1/z + 1/5))/(z + 5)]`


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`lim_(y -> 1)[(2y - 2)/(root(3)(7 + y) - 2)]`


Evaluate the following limit :

`lim_(x -> 1) [(x + x^3 + x^5 + ... + x^(2"n" - 1) - "n")/(x - 1)]`


In problems 1 – 6, using the table estimate the value of the limit.

`lim_(x -> 2) (x - 2)/(x^2 - x - 2)`

x 1.9 1.99 1.999 2.001 2.01 2.1
f(x) 0.344820 0.33444 0.33344 0.333222 0.33222 0.332258

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> 0) (cos x - 1)/x`

x – 0.1  – 0.01 – 0.001 0.0001 0.01 0.1
f(x) 0.04995 0.0049999 0.0004999 – 0.0004999 – 0.004999 – 0.04995

Write a brief description of the meaning of the notation `lim_(x -> 8) f(x)` = 25


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`lim_(sqrt(x) -> 3) (x^2 - 81)/(sqrt(x) - 3)`


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`lim_(x -> 0) (sinalphax)/(sinbetax)`


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`lim_(x -> oo) ((x^2 - 2x + 1)/(x^2 -4x + 2))^x`


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The value of `lim_(x -> 0) sinx/sqrt(x^2)` is


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