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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Evaluate the following limit : limx→0[log(3-x)-log(3+x)x]

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प्रश्न

Evaluate the following limit : 

`lim_(x -> 0) [(log(3 - x) - log(3 + x))/x]`

बेरीज
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उत्तर

`lim_(x -> 0) (log(3 - x) - log(3 + x))/x`

= `lim_(x -> 0) 1/x log ((3 - x)/(3 + x))`

= `lim_(x -> 0) log((3 - x)/(3 + x))^(1/x)`

= `lim_(x -> 0) log((1 - x/3)/(1 + x/3))^(1/x)`

= `log[lim_(x -> 0) ((1 - x/3)^(1/x))/(1 + x/3)^(1/x)]`

= `log[{lim_(x -> 0)(1 - x/3)^((-3)/x)}^((-1)/3)/{lim_(x -> 0)(1 + x/3)^(3/x)}^(1/3)]`

= `log("e"^(-1/3)/("e"^(1/3)))   ...[because x -> 0","  ± x/3 -> 0  "and" lim_(x -> 0) (1 + x)^(1/x) = "e"]`

= `log "e"^(-(2)/3)`

= `-2/3*log "e"`

= `-2/3(1)`

= `-2/3`

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पाठ 7: Limits - Exercise 7.6 [पृष्ठ १५४]

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