मराठी

Evaluate the following: d∫tan2xsec4xdx

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प्रश्न

Evaluate the following:

`int tan^2x sec^4 x"d"x`

बेरीज
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उत्तर

Let I = `int tan^2x sec^4 x"d"x`

= `int tan^2x sec^2x sec^2 x"d"x`

= `int tan^2x (1 + tan^2x)sec^2 x"d"x`

Put tan x = t

⇒ `sec^2x "d"x` = dt

∴ I = `int "t"^2(1 + "t"^2)"dt"`

= `int("t"^2 + "t"^4)"dt"`

= `"t"^3/3 + "t"^5/5 + "C"`

= `(tan^5x)/5 + (tan^3x)/3 + "C"`

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पाठ 7: Integrals - Exercise [पृष्ठ १६४]

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