Question

Energy of an electron in second Bohr orbit is −3.4 eV. Calculate its kinetic energy and potential energy in third Bohr orbit.

Answer 1

Given: Energy in the second Bohr orbit (E₂) = −3.4 eV

For hydrogen atom (E_n) = `(-13.6)/n^2` eV

Energy in third orbit (n = 3):

E₃ = `(-13.6)/3^2` eV

= `(-13.6)9` eV

= −1.51 eV

For Bohr’s orbit:

Total Energy (E) = K + U

K = −E

U = 2 E

Calculate K.E. and P.E. in the 3^rd orbit:

K₃ = −E_3​

= 1.51 eV

U₃ ​= 2 E_3​

= 2(−1.51)

= −3.02 eV