मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

During nuclear explosion, one of the products is 90Sr with half-life of 28.1 years. If 1μg of 90Sr was absorbed in the bones of a newly born baby instead of calcium, how much of it will remain after

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प्रश्न

During nuclear explosion, one of the products is 90Sr with half-life of 28.1 years. If 1μg of 90Sr was absorbed in the bones of a newly born baby instead of calcium, how much of it will remain after 10 years and 60 years if it is not lost metabolically?

संख्यात्मक
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उत्तर

k = `0.693/t_(1//2)`

= `0.693/28.1`

= 2.466 × 10−2 y−1

[A]0 = 1 µg

After 10 years,

k = `2.303/t log_10  ([A]_0]/([A])`

⇒ 2.466 × 10−2 = `2.303/10 log_10  1/([A])`

`1/([A]) = "antilog"_10 [(2.466 xx 10^-2 xx 10)/2.303]`

`1/([A]) = "antilog"_10 [0.2466/2.303]`

`1/([A])` = antilog10 (0.10707)

`1/([A])` = 1.2796

∴ [A] = `[1/1.2796]`

[A] = 0.7815 µg

After 60 years,

`1/([A]) = "antilog"_10 [(2.466 xx 10^-2 xx 60)/2.303]`

`1/([A]) = "antilog"_10 [1.4796/2.303]`

`1/([A])` = antilog10 [0.6424]

`1/([A])` = 4.39

[A] = `1/4.39`

[A] = 0.227 µg

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पाठ 3: Chemical Kinetics - 'NCERT TEXT-BOOK' Exercises [पृष्ठ २८०]

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नूतन Chemistry [English] Class 12 ISC
पाठ 3 Chemical Kinetics
'NCERT TEXT-BOOK' Exercises | Q 4.17 | पृष्ठ २८०
एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 3 Chemical Kinetics
Exercises | Q 3.17 | पृष्ठ ८७

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